Question

which scenario best fits the graph shown below? a machine at a factory can spool 2 yards of twine per minute. the inputs are the number of minutes that have passed and the outputs are the number of yards of twine remaining to be spooled. the graph shows the time it takes for 45 yards of twine to be spun. a machine at a factory can spool 2 yards of twine per minute. the inputs are the number of minutes that have passed and the outputs are the number of yards of twine remaining to be spooled. the graph shows the time it takes for 54 yards of twine to be spun a machine at a factory can spool 3 yards of twine per minute. the inputs are the number of minutes that have passed and the outputs are the number of yards of twine remaining to be spooled. the graph shows the time it takes for 54 yards of twine to be spun a machine at a factory can spool 3 yards of twine per minute. the inputs are the number of minutes that have passed and the outputs are the number of yards of twine remaining to be spooled. the graph shows the time it takes for 45 yards of twine to be spun

Explanation:

Step1: Find initial total yarn

The y-intercept is the starting yarn. At time=0, yarn=60 yards.

Step2: Calculate spooling rate

Use point (3,45). Yarn used: $60-45=15$ yards over 3 mins. Rate: $\frac{15}{3}=5$ yards/min.

Step3: Match to scenario

Check options: rate=5 yd/min, total=60 yd, output=remaining yarn.

Answer:

A machine at a factory can spool 5 yards of twine per minute. The inputs are the number of minutes that have passed and the outputs are the number of yards of twine remaining to be spooled.
The graph shows the time it takes for 60 yards of twine to be spun.