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without graphing, describe the shape of the graph of the function. find…

Question

without graphing, describe the shape of the graph of the function. find the second coordinates of the points with first coordinates 0 and 1. f(x)=21.4^x the graph dropdown arrow exponentially grows. exponentially decays.

Explanation:

Step1: Identify growth/decay type

For exponential functions $f(x)=a^{kx}$, if $k>0$, it grows. Here $k=1.4>0$, so the graph exponentially grows.

Step2: Calculate f(0)

Substitute $x=0$ into $f(x)$:
$f(0)=2^{1.4\times0}=2^0=1$

Step3: Calculate f(1)

Substitute $x=1$ into $f(x)$:
$f(1)=2^{1.4}\approx2.639$

Answer:

The graph exponentially grows.
Second coordinate for $x=0$: $1$
Second coordinate for $x=1$: $\approx2.639$