write 2(2)(2)(2)(2)(2)(2) in exponential form. $2^8$ $2^7$ $8 \\times 2…

$write 2(2)(2)(2)(2)(2)(2) in exponential form. $2^8$ $2^7$ $8 \\times 2…$

write 2(2)(2)(2)(2)(2)(2) in exponential form.
$2^8$
$2^7$
$8 \times 2$
$8^2$

Count the repeated factor 2: there are 8 instances of 2 being multiplied together.

Exponential form is base$^{\text{number of factors}}$, so $2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 2^8$

$2^8$