Question

01 question (4 points)
how many atoms of titanium are there in 1.42 mole of each of the following?
1st attempt
part 1 (1 point)
ilmenite, fetio₃ ti atoms
part 2 (1 point)
titanium(iv) chloride ti atoms
part 3 (1 point)
ti₂o₃ ti atoms
part 4 (1 point)
ti₃o₅ ti atoms

Explanation:

Step1: Recall Avogadro's number

1 mole of any substance contains $6.022\times 10^{23}$ entities.

Step2: Determine moles of Ti in each compound

Part 1: In $FeTiO_3$

There is 1 mole of Ti per mole of $FeTiO_3$. So in 1.42 moles of $FeTiO_3$, moles of Ti = 1.42 moles.
Number of Ti atoms = $1.42\times6.022\times 10^{23}=8.55124\times 10^{23}$ atoms.

Part 2: In titanium(IV) chloride ($TiCl_4$)

There is 1 mole of Ti per mole of $TiCl_4$. So in 1.42 moles of $TiCl_4$, moles of Ti = 1.42 moles.
Number of Ti atoms = $1.42\times6.022\times 10^{23}=8.55124\times 10^{23}$ atoms.

Part 3: In $Ti_2O_3$

There are 2 moles of Ti per mole of $Ti_2O_3$. So moles of Ti in 1.42 moles of $Ti_2O_3$ is $1.42\times2 = 2.84$ moles.
Number of Ti atoms = $2.84\times6.022\times 10^{23}=1.700248\times 10^{24}$ atoms.

Part 4: In $Ti_3O_5$

There are 3 moles of Ti per mole of $Ti_3O_5$. So moles of Ti in 1.42 moles of $Ti_3O_5$ is $1.42\times3=4.26$ moles.
Number of Ti atoms = $4.26\times6.022\times 10^{23}=2.565372\times 10^{24}$ atoms.

Answer:

Part 1: $8.55124\times 10^{23}$
Part 2: $8.55124\times 10^{23}$
Part 3: $1.700248\times 10^{24}$
Part 4: $2.565372\times 10^{24}$