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(02.01 mc) the following orbital notation is for which element? 1s 2s 2…

Question

(02.01 mc)
the following orbital notation is for which element?

1s 2s 2p

o a b
o b n
o c f
o d o

pregunta 8 (3 puntos)
(02.03 mc)
the partial electron - configuration of an atom with 11 electrons is shown.
1s²2s²2p⁶x

which of the following does x represent?

o a 3s¹
o b 2d¹
o c 3p¹
o d 4s¹

Explanation:

Step1: Count electrons in orbital diagram

The 1s orbital has 2 electrons (paired), the 2s orbital has 2 electrons (paired), and the 2p orbitals have 3 un - paired electrons. So in total, there are \(2 + 2+3=7\) electrons.

Step2: Identify element by electron number

The atomic number of an element is equal to the number of electrons in a neutral atom. Nitrogen (N) has an atomic number of 7.

Step3: Analyze second question

For an atom with 11 electrons, the electron - filling order is \(1s^22s^22p^63s^1\) according to the Aufbau principle. After filling the 1s (2 electrons), 2s (2 electrons) and 2p (6 electrons) orbitals, the remaining 1 electron goes into the 3s orbital.

Answer:

  1. B. N
  2. A. \(3s^1\)