Question

a 10 kg block is pushed across a table with a 40 n applied force. if the force of friction is 15 n, what is the net force (fnet) on the block? 5/10

Explanation:

Step1: Identify forces acting

The applied force $F_{applied}=40\ N$ and frictional force $F_{friction}=15\ N$. The frictional force acts in the opposite direction of the applied force.

Step2: Calculate net - force

The net - force $F_{net}$ is given by the formula $F_{net}=F_{applied}-F_{friction}$. Substitute the values: $F_{net}=40 - 15$.
$F_{net}=25\ N$

Answer:

$25\ N$