QUESTION IMAGE
Question
- a kilogram is = to how many pounds?
- define temperature.
- what is fahrenheit?
- what is celsius?
- what equation do you use to convert from degrees celsius (°c) to degrees fahrenheit (°f)?
- imagine a friend from canada calls you and says that it is 45°c outside. what is the temperature in degrees fahrenheit? to convert to degrees fahrenheit, substitute 45°c into the above equation and solve.
- what equation do you use to convert from degrees fahrenheit (°f) to degrees celsius (°c)?
- if it is 75°f outside, what is the temperature in degrees celsius?
- which is warmer, 25°f or 25°c?
Step1: Kilogram - pound conversion
1 kilogram is approximately 2.20462 pounds.
Step2: Define temperature
Temperature is a measure of the average kinetic energy of the particles in a substance.
Step3: Define Fahrenheit
Fahrenheit is a temperature scale where water freezes at 32°F and boils at 212°F at standard atmospheric pressure.
Step4: Define Celsius
Celsius is a temperature scale where water freezes at 0°C and boils at 100°C at standard atmospheric pressure.
Step5: Celsius - Fahrenheit conversion formula
The formula to convert from Celsius ($C$) to Fahrenheit ($F$) is $F=\frac{9}{5}C + 32$.
Step6: Convert 45°C to Fahrenheit
Substitute $C = 45$ into the formula: $F=\frac{9}{5}\times45+32$. First, $\frac{9}{5}\times45=9\times9 = 81$. Then $81 + 32=113$. So 45°C is 113°F.
Step7: Fahrenheit - Celsius conversion formula
The formula to convert from Fahrenheit ($F$) to Celsius ($C$) is $C=\frac{5}{9}(F - 32)$.
Step8: Convert 75°F to Celsius
Substitute $F = 75$ into the formula: $C=\frac{5}{9}(75 - 32)=\frac{5}{9}\times43\approx23.9$°C.
Step9: Compare 25°F and 25°C
Convert 25°F to Celsius: $C=\frac{5}{9}(25 - 32)=\frac{5}{9}\times(- 7)\approx - 3.9$°C. Since 25°C > - 3.9°C, 25°C is warmer.
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- Approximately 2.20462 pounds
- A measure of the average kinetic energy of the particles in a substance
- A temperature scale where water freezes at 32°F and boils at 212°F at standard atmospheric pressure
- A temperature scale where water freezes at 0°C and boils at 100°C at standard atmospheric pressure
- $F=\frac{9}{5}C + 32$
- 113°F
- $C=\frac{5}{9}(F - 32)$
- Approximately 23.9°C
- 25°C