Question

1. write the simple lewis - dot structure for each of the following atoms. a. i(z = 53) b. al(z = 13) c. xe(z = 54) d. sr(z = 38)

Explanation:

Step1: Determine valence electrons for I

Iodine (I) has atomic number \(Z = 53\). Its electron - configuration shows that it has 7 valence electrons. The Lewis - dot structure has the symbol 'I' with 7 dots around it.

Step2: Determine valence electrons for Al

Aluminum (Al) has atomic number \(Z=13\). Its electron - configuration gives it 3 valence electrons. The Lewis - dot structure has the symbol 'Al' with 3 dots around it.

Step3: Determine valence electrons for Xe

Xenon (Xe) has atomic number \(Z = 54\). It is a noble gas with 8 valence electrons. The Lewis - dot structure has the symbol 'Xe' with 8 dots around it.

Step4: Determine valence electrons for Sr

Strontium (Sr) has atomic number \(Z = 38\). It has 2 valence electrons. The Lewis - dot structure has the symbol 'Sr' with 2 dots around it.

Answer:

a. I: I with 7 dots around it
b. Al: Al with 3 dots around it
c. Xe: Xe with 8 dots around it
d. Sr: Sr with 2 dots around it