Question

11/15 consider the compound zirconium(v) phosphate: the % zirconium is 37 % and the % phosphorous is 21 %. determine the % oxygen in zirconium(v) phosphate using the given data. -report 2 significant digits and the % sign ~

Explanation:

Step1: Sum given element percentages

$\% \text{Zr} + \% \text{P} = 37\% + 21\% = 58\%$

Step2: Subtract sum from 100%

$\% \text{O} = 100\% - 58\% = 42\%$

Answer:

42%