Question

11 fill in the blank 1 point how many grams of pb(no₃)₂ can be dissolved in 300 g of water at 50 °c? 50 g × 85 g 135 g 255 g 20 g previous

Explanation:

Step1: Determine solubility data

We need the solubility of $Pb(NO_3)_2$ in water at $50^{\circ}C$. Typically, the solubility of $Pb(NO_3)_2$ in water at $50^{\circ}C$ is around 85 g per 100 g of water.

Step2: Calculate for 300 g of water

If 85 g can dissolve in 100 g of water, for 300 g of water, we use the proportion $\frac{85}{100}=\frac{x}{300}$, where $x$ is the mass of $Pb(NO_3)_2$ that can dissolve in 300 g of water. Cross - multiplying gives $100x = 85\times300$, so $x=\frac{85\times300}{100}=255$ g.

Answer:

255 g