Question

1. how many grams of cl2 are there in 7.25 mol fecl3?

Explanation:

Step1: Determine Cl atoms in $FeCl_3$

1 mol $FeCl_3$ has 3 mol Cl atoms. So 7.25 mol $FeCl_3$ has $7.25\times3 = 21.75$ mol Cl atoms.

Step2: Relate to $Cl_2$ moles

1 mol $Cl_2$ has 2 mol Cl atoms. So moles of $Cl_2$ is $\frac{21.75}{2}=10.875$ mol.

Step3: Calculate mass of $Cl_2$

Molar - mass of $Cl_2$ is $2\times35.45 = 70.9$ g/mol. Mass = moles $\times$ molar - mass, so mass of $Cl_2$ is $10.875\times70.9 = 761.03$ g.

Answer:

761.03 g