Question

1. choose the the answer.

a 20.0 l sample of nitrogen inside a rigid, metal container at 20.0 °c is placed inside an oven. the initial pressure was at 3.00 atm. what is the pressure after its temperature increases to 40.0 °c?
○ 1.50 atm
○ 2.81 atm
○ 3.20 atm

Explanation:

Step1: Convert temp to Kelvin

$T_1 = 20.0 + 273.15 = 293.15\ \text{K}$
$T_2 = 40.0 + 273.15 = 313.15\ \text{K}$

Step2: Apply Gay-Lussac's Law

Gay-Lussac's Law: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$
Rearrange to solve for $P_2$: $P_2 = P_1 \times \frac{T_2}{T_1}$

Step3: Substitute values

$P_2 = 3.00\ \text{atm} \times \frac{313.15}{293.15}$
$P_2 = 3.00\ \text{atm} \times 1.0682 \approx 3.20\ \text{atm}$

Answer:

3.20 atm