Question

1. in the compound ch3oh the shape around the c atom is _i_ and the shape around the o atom is _ii_. the statement above is best completed by the answers in row:

row i ii
□ trigonal pyramidal linear
□ tetrahedral linear
□ trigonal pyramidal bent
□ tetrahedral bent

Explanation:

Step1: Analyze C - atom in $CH_3OH$

The carbon atom in $CH_3OH$ has 4 bonding pairs and 0 lone - pairs. According to VSEPR (Valence - Shell Electron - Pair Repulsion) theory, the electron - pair geometry and molecular geometry around an atom with 4 bonding pairs and 0 lone - pairs is tetrahedral.

Step2: Analyze O - atom in $CH_3OH$

The oxygen atom in $CH_3OH$ has 2 bonding pairs and 2 lone - pairs. According to VSEPR theory, the electron - pair geometry around the oxygen atom is tetrahedral, but the molecular geometry (considering only the atoms) is bent due to the repulsion of the lone - pairs.

Answer:

tetrahedral, bent