Question

1. two children are playing on a seesaw trying to balance. if the child on the left sits 1.5 meters away from the fulcrum and weighs 25 kg, and the child on the right weighs 35 kg, how far away from the pivot point will the child on the right have to sit?

○ 1.5 m
○ 1.07 m
○ 0.75 m
○ 1.75 m

Explanation:

Step1: Set up torque balance

Torque left = Torque right: $m_1 g d_1 = m_2 g d_2$

Step2: Cancel common terms

Cancel $g$: $m_1 d_1 = m_2 d_2$

Step3: Solve for $d_2$

Rearrange: $d_2 = \frac{m_1 d_1}{m_2}$

Step4: Substitute values

$d_2 = \frac{25 \times 1.5}{35} = \frac{37.5}{35} \approx 1.07$ m

Answer:

1.07 m