Question

14 calculate the energy possessed by a single photon whose frequency is 9.50 x 10^13 1/s. * (0.5 points) 6.31 x 10^-50 j 6.96 x 10^-18 j 3.50 x 10^7 j 4.19 x 10^-13 j 6.29 x 10^-20 j 2.86 x 10^-8 j

Explanation:

Step1: Recall Planck's equation

$E = h
u$, where $E$ is energy of photon, $h = 6.63\times 10^{-34}\ J\cdot s$ (Planck's constant) and $
u$ is frequency.

Step2: Substitute values

Given $
u=9.50\times 10^{13}\ Hz$ (since $1/s = Hz$), then $E=(6.63\times 10^{-34}\ J\cdot s)\times(9.50\times 10^{13}\ Hz)$.

Step3: Calculate result

$E = 6.63\times9.50\times 10^{-34 + 13}\ J=62.985\times 10^{-21}\ J\approx6.30\times 10^{-20}\ J$

Answer:

None of the provided options are correct. The correct energy value is approximately $6.30\times 10^{-20}\ J$.