Question

1. given that h = 6.626 x 10^(-34) and e = hf, what is the frequency of light that has an energy of 3.15 x 10^(-19) j? round your answer to the nearest hundredth. clear all 4.75 x 10^14 hz 2.09 x 10^52 hz 4.75 x 10^(-14) hz 2.09 x 10^(-52) hz

Explanation:

Step1: Rearrange the formula

Given $E = hf$, we can solve for $f$ by dividing both sides of the equation by $h$. So $f=\frac{E}{h}$.

Step2: Substitute the given values

We know that $E = 3.15\times10^{-19}\text{ J}$ and $h = 6.626\times 10^{-34}\text{ J}\cdot\text{s}$. Then $f=\frac{3.15\times 10^{-19}}{6.626\times 10^{-34}}$.
Using the rule of exponents $\frac{a\times10^{m}}{b\times10^{n}}=\frac{a}{b}\times10^{m - n}$, we have $f=\frac{3.15}{6.626}\times10^{-19+34}$.
$\frac{3.15}{6.626}\approx0.475$, and $- 19 + 34=15$. So $f\approx0.475\times10^{15}\text{ Hz}=4.75\times10^{14}\text{ Hz}$.

Answer:

A. $4.75\times 10^{14}\text{ Hz}$