Question

(\frac{16.83}{15} - 0.46) nd the answer appropriately s your answer numerically using the appropriate number of significant figures or decimal plac v available hint(s) mit previous answers incorrect; try again; 6 attempts remaining

Explanation:

Step1: Calculate the division

First, we calculate $\frac{16.83}{15}$.
$\frac{16.83}{15}= 1.122$

Step2: Subtract 0.46

Then we subtract 0.46 from the result of the division: $1.122 - 0.46 = 0.662$
Now, we need to consider significant figures. The number 16.83 has four significant figures, 15 has two, and 0.46 has two. When dividing, the result should have two significant figures (from 15), but wait, actually, let's re - evaluate. The rule for addition/subtraction is about decimal places. 1.122 has three decimal places, 0.46 has two. So when we subtract, the result should be rounded to two decimal places? Wait, no, let's check the original numbers. $\frac{16.83}{15}$: 16.83 is precise to the hundredth place, 15 is an exact integer (maybe? If 15 is a counted number, it's exact). So $\frac{16.83}{15}=1.122$ (exact in terms of the division). Then 1.122 - 0.46. 0.46 is precise to the hundredth place. So the result should be precise to the hundredth place. 1.122 - 0.46 = 0.662, which rounds to 0.66 (if we consider two decimal places) or, wait, maybe the significant figures for the division: 16.83 has 4 sig figs, 15 has 2, so $\frac{16.83}{15}$ should have 2 sig figs? Wait, no, 15 could be considered as having infinite sig figs if it's a defined quantity (like 15 items). Let's assume that 15 is exact. Then 16.83/15 = 1.122. Then 1.122 - 0.46. 0.46 has two decimal places, 1.122 has three. The result of subtraction should be rounded to two decimal places. 0.662 rounded to two decimal places is 0.66. But wait, maybe the problem expects us to just do the calculation without over - thinking sig figs first. Let's recalculate:

$\frac{16.83}{15}=1.122$

$1.122-0.46 = 0.662$

If we consider significant figures for the subtraction: the least number of decimal places in the numbers being subtracted is two (0.46 has two decimal places, 1.122 has three). So we round the result to two decimal places: 0.66. But wait, maybe the original numbers: 16.83 has four significant figures, 15 has two, 0.46 has two. When we do $\frac{16.83}{15}$, the result should have two significant figures? Wait, no, the rule for division is that the result has the same number of significant figures as the least precise measurement. 15 has two, 16.83 has four, so $\frac{16.83}{15}\approx1.1$ (two significant figures). Then 1.1 - 0.46 = 0.64. But this is conflicting. Wait, maybe the problem is just a simple calculation without strict sig fig rules for the purpose of the question. Let's do the exact calculation:

$\frac{16.83}{15}=1.122$

$1.122 - 0.46=0.662$

If we take three significant figures, 0.662 is three. But let's check the numbers: 16.83 (four), 15 (exact), 0.46 (two). The subtraction: 1.122 (three decimal places) - 0.46 (two decimal places) = 0.662. The number of decimal places in the result should be equal to the least number of decimal places in the terms, which is two. So 0.66 (rounded to two decimal places). But maybe the problem expects the un - rounded result? Wait, no, let's check the calculation again.

Wait, 16.83 divided by 15: 15*1 = 15, 16.83 - 15 = 1.83, 1.83/15 = 0.122, so total is 1.122. Then 1.122 - 0.46: 1.122 - 0.4 = 0.722, 0.722 - 0.06 = 0.662. So the result is 0.662. If we consider significant figures, 0.46 has two significant figures? No, 0.46 has two significant figures (the 4 and 6). 16.83 has four, 15 has two. When dividing, 16.83/15: since 15 has two, the result should have two? Wait, 15 could be a whole number with infinite sig figs (like 15.000...). If 15 is exact, then 16.83/15 has four sig figs (1.122). Then subtracting 0.46 (two sig figs in the decimal part? No, 0.46 has two sig figs overall). The rule for addition/subtraction is based on decimal places, not sig figs. So 1.122 (three decimal places) - 0.46 (two decimal places) = 0.662, which should be rounded to two decimal places, giving 0.66. But maybe the problem just wants the value as 0.66 (or 0.662). Let's see, maybe the initial calculation is just to compute the expression.

Answer:

0.66 (or 0.662, depending on sig fig interpretation. But likely 0.66 when rounded to two decimal places)