Question

15 fawn, joey, and caleb play a board game. fawn’s score is $-28$ points. joey’s score is $\frac{4}{7}$ of fawn’s score. caleb scores $\frac{3}{4}$ as many points as joey. how many points do they score in all?
a $-56$
c $-16$
b $-44$
d $-12$

Explanation:

Step1: Calculate Joey's score

Joey's score is $\frac{4}{7}$ of Fawn's score. Fawn's score is -28. So Joey's score = $\frac{4}{7} \times (-28)$ = -16.

Step2: Calculate Caleb's score

Caleb's score is $\frac{3}{4}$ of Joey's score. Joey's score is -16. So Caleb's score = $\frac{3}{4} \times (-16)$ = -12.

Step3: Calculate total score

Total score = Fawn's score + Joey's score + Caleb's score = -28 + (-16) + (-12) = -28 -16 -12 = -56.

Answer:

A -56