Question

1. use the equation you built in the previous problem.

calculate how many moles of $na_2o$ would you expect to be produced if 0.0777 moles $nahco_3$ decompose according to reaction #3:
$2nahco_3 \
ightarrow na_2o + 2co_2 + h_2o$
i need a hint
mole $na_2o$
the answer to this question depends on your answers to previous questions.
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Explanation:

Step1: Identify mole ratio

From the balanced equation $2\text{NaHCO}_3
ightarrow \text{Na}_2\text{O} + 2\text{CO}_2 + \text{H}_2\text{O}$, the mole ratio of $\text{NaHCO}_3$ to $\text{Na}_2\text{O}$ is $2:1$.

Step2: Calculate moles of $\text{Na}_2\text{O}$

Moles of $\text{Na}_2\text{O} = \frac{\text{Moles of NaHCO}_3}{2}$
$\text{Moles of Na}_2\text{O} = \frac{0.0777}{2}$

Answer:

0.03885 moles of $\text{Na}_2\text{O}$