Question

1. - / 1 pointsdetailsmy notesask your teacherpractice anotherosuniphys1 3.4.p.063.a care package is dropped out of a cargo plane and lands in the forest. if we assume the care package speed on impact is 47 m/s (105 mph), then what is its acceleration during landing (in m/s²)? assume the trees and snow stop it over a distance of 3.7 m. (assume the positive direction is toward the earth. indicate the direction with the sign of your answer.)$\boldsymbol{square}$ m/s²resourcesreading

Explanation:

Step1: List known variables

Initial velocity $v_0 = 47\ \text{m/s}$, final velocity $v = 0\ \text{m/s}$, displacement $d = 3.7\ \text{m}$

Step2: Select kinematic equation

Use $v^2 = v_0^2 + 2ad$ to solve for acceleration $a$

Step3: Rearrange for acceleration

$a = \frac{v^2 - v_0^2}{2d}$

Step4: Substitute values

$a = \frac{0^2 - (47)^2}{2\times3.7} = \frac{-2209}{7.4}$

Answer:

$-298.51\ \text{m/s}^2$