Question

1. (03.05 mc) a hot air balloon holds 4,328 cubic meters of helium. the density of helium is 0.1785 kilograms per cubic meter. how many kilograms of helium does the balloon contain, rounded to the nearest tenth of a kilogram? (5 points)

3,747.9 kg
3,875.3 kg
772.5 kg
4,983.2 kg

Explanation:

Step1: Recall mass-density-volume formula

Mass = Density × Volume

Step2: Substitute given values

$\text{Mass} = 0.1785 \, \text{kg/m}^3 \times 4328 \, \text{m}^3$

Step3: Calculate the product

$0.1785 \times 4328 = 772.548$

Step4: Round to nearest tenth

$772.548 \approx 772.5$

Answer:

772.5 kg