Question

1. construct the mole ratio needed to calculate how many moles of $ce{na_{2}co_{3}}$ that are produced from 0.0777 mole $ce{nahco_{3}}$ if reaction #4 occurs.$ce{2nahco_{3} -> na_{2}co_{3} + co_{2} + h_{2}o}$begin with the 0.0777 moles $ce{nahco_{3}}$ reacting in the experiment.$\frac{\text{a units}}{\text{ }} \times \frac{\text{c units}}{\text{e units}} = ? \text{mol} ce{na_{2}co_{3}}$i need a hintchoices:0.0777mole $ce{co_{2}}$mole $ce{na_{2}co_{3}}$mole $ce{nahco_{3}}$12

Explanation:

Step1: Identify mole ratio

From balanced reaction: $\frac{1\ \text{mol}\ \text{Na}_2\text{CO}_3}{2\ \text{mol}\ \text{NaHCO}_3}$

Step2: Set up conversion

Multiply given moles by ratio:
$0.0777\ \text{mol}\ \text{NaHCO}_3 \times \frac{1\ \text{mol}\ \text{Na}_2\text{CO}_3}{2\ \text{mol}\ \text{NaHCO}_3}$

Step3: Calculate result

Cancel units and compute: $\frac{0.0777}{2} = 0.03885$

Answer:

Filled equation:
$0.0777\ \text{mole NaHCO}_3 \times \frac{1\ \text{mole Na}_2\text{CO}_3}{2\ \text{mole NaHCO}_3} = 0.03885\ \text{mol Na}_2\text{CO}_3$

Final moles of $\text{Na}_2\text{CO}_3$: $0.03885$