Question

a 200 kg sled is pushed forward, producing an acceleration of 2 m/s². later, a second person applies and the acceleration increases to 3 m/s². how much additional force did the second person apply?
a) 80 n
b) 100 n
c) 200 n
d) 400 n

Explanation:

Step1: Calculate initial force

Using Newton's second - law $F = ma$. Given mass $m = 200$ kg and initial acceleration $a_1=2$ m/s², the initial force $F_1=ma_1$. So $F_1 = 200\times2=400$ N.

Step2: Calculate final force

With mass $m = 200$ kg and final acceleration $a_2 = 3$ m/s², the final force $F_2=ma_2$. So $F_2=200\times3 = 600$ N.

Step3: Calculate additional force

The additional force $\Delta F=F_2 - F_1$. So $\Delta F=600 - 400=200$ N.

Answer:

b) 200 N