Question

23 multiple choice 1 point a new high - frequency radiographic system is being released to a customer for first clinical use. the applications person states that the aec density controls are in 20% increments. if a normal aec exposure of the hip is 24 mas, a repeat exposure at +2 would yield a mas value of 26 mas. 29 mas. 34 mas. 48 mas.

Explanation:

Step1: Determine the increment factor

Since each increment is 20% and we have +2 increments, the total percentage increase is $2\times20\% = 40\%$. In decimal form, 40% is 0.4.

Step2: Calculate the new mAs value

The original mAs value is 24 mAs. To find the new value, we multiply the original value by $(1 + 0.4)$. So the new mAs value is $24\times(1 + 0.4)=24\times1.4 = 33.6\approx34$ mAs.

Answer:

34 mAs