Question

1. a sample of hydrogen gas occupies 3.0 l at 960 torr in a balloon. if the temperature is kept constant, which expression represents the volume of hydrogen gas in liters when the pressure is lowered to 760 torr? 760 torr(3.0 l)/960 torr; 960 torr(3.0 l)/760 torr; 3.0 l/760 torr; 3.0 l/960 torr

Explanation:

Step1: Recall Boyle's Law

Boyle's Law states that for a fixed amount of gas at constant temperature, \( P_1V_1 = P_2V_2 \), where \( P_1 \) and \( V_1 \) are the initial pressure and volume, and \( P_2 \) and \( V_2 \) are the final pressure and volume.

Step2: Solve for \( V_2 \)

We need to find \( V_2 \), so rearrange the formula: \( V_2=\frac{P_1V_1}{P_2} \).
Here, \( P_1 = 960 \) torr, \( V_1 = 3.0 \) L, and \( P_2 = 760 \) torr. Substituting these values in, we get \( V_2=\frac{960\ \text{torr} \times 3.0\ \text{L}}{760\ \text{torr}} \).

Answer:

960 torr(3.0L)/760 torr (the option with this expression)