Question

2c₄h₁₀(g) + 13o₂(g) → 8co₂(g) + 10h₂o(g)
element | number of atoms
c |
h |
o |

Explanation:

Step1: Calculate C atoms

In \(2C_4H_{10}\), each \(C_4H_{10}\) has 4 C atoms, so 2 molecules have \(2\times4 = 8\) C atoms. On the product side, \(8CO_2\) has \(8\times1 = 8\) C atoms (since each \(CO_2\) has 1 C). So total C atoms: 8.

Step2: Calculate H atoms

In \(2C_4H_{10}\), each \(C_4H_{10}\) has 10 H atoms, so 2 molecules have \(2\times10 = 20\) H atoms. On the product side, \(10H_2O\) has \(10\times2 = 20\) H atoms (since each \(H_2O\) has 2 H). So total H atoms: 20.

Step3: Calculate O atoms

In \(13O_2\), each \(O_2\) has 2 O atoms, so 13 molecules have \(13\times2 = 26\) O atoms. On the product side, \(8CO_2\) has \(8\times2 = 16\) O atoms and \(10H_2O\) has \(10\times1 = 10\) O atoms. Total product O: \(16 + 10 = 26\). So total O atoms: 26.

Answer:

For C: 8
For H: 20
For O: 26