QUESTION IMAGE
Question
- modeling with mathematics write and solve an inequality that represents how many $20 bills you can withdraw from the account without going below the minimum balance. (see example 4.) your current balance is $320.00 the minimum balance is $100.00. would you like to make another transaction?
Step1: Let the number of $20 bills be $x$.
The amount withdrawn is $20x$.
Step2: Set up the inequality.
The current balance is $320$. After withdrawal, the balance should be at least the minimum balance of $100$. So, $320 - 20x\geq100$.
Step3: Solve the inequality for $x$.
Subtract 320 from both sides: $- 20x\geq100 - 320$, which simplifies to $-20x\geq - 220$.
Divide both sides by - 20. When dividing an inequality by a negative number, the direction of the inequality sign changes. So, $x\leq\frac{-220}{-20}$, which gives $x\leq11$.
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The inequality is $320 - 20x\geq100$ and the solution is $x\leq11$, meaning you can withdraw at most 11 $20 - dollar bills.