Question

1. what is the equation for hookes law?

$f_{elastic} = \frac{1}{2}m(\delta v)^2$
$f_{elastic} = kx$
$f_{elastic} = ke_i + pe_i$
$f_{elastic} = mgh$

Explanation:

Hooke's law states that the elastic force exerted by a spring is directly proportional to the displacement $x$ from its equilibrium position, where $k$ is the spring constant. The other options represent kinetic energy ($\frac{1}{2}m(\Delta v)^2$), conservation of mechanical energy ($KE_i + PE_i$), and gravitational potential energy ($mgh$), which are unrelated to Hooke's law.

Answer:

B. $F_{elastic} = kx$