Question

a 50.0 ml solution of ca(oh)₂ with an unknown concentration was titrated with 0.340 m hno₃. to reach the endpoint, a total of 28.4 ml of hno₃ was required. what quantity in moles of hno₃ are used in the titration?

Explanation:

Step1: Recall molarity formula

Molarity ($M$) = $\frac{n}{V}$, where $n$ is moles and $V$ is volume in liters.

Step2: Convert volume to liters

$V = 28.4\ mL=28.4\times10^{- 3}\ L$

Step3: Rearrange formula to find moles

$n = M\times V$. Given $M = 0.340\ M$, then $n=0.340\ mol/L\times28.4\times10^{-3}\ L$

Step4: Calculate moles

$n = 0.340\times28.4\times10^{-3}=9.656\times10^{-3}\ mol$

Answer:

$9.656\times10^{-3}$