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c₃h₈(g) + 5o₂(g) → 3co₂(g) + 4h₂o(g) the reaction began with 65.0 g c₃h…

Question

c₃h₈(g) + 5o₂(g) → 3co₂(g) + 4h₂o(g)
the reaction began with 65.0 g c₃h₈ and 105 l o₂. 41.3 g c₃h₈ were used during the reaction. what mass of c₃h₈ remains?
? g c₃h₈

Explanation:

Step1: Identify initial and used mass

Initial mass of \( \ce{C3H8} \) is \( 65.0 \, \text{g} \), used mass is \( 41.3 \, \text{g} \).

Step2: Calculate remaining mass

Remaining mass = Initial mass - Used mass = \( 65.0 - 41.3 \)

Answer:

\( 23.7 \)