Question

600.0 ml of a 0.490 m solution of licl is diluted to 900.0 ml. what is the new concentration of the solution?

Explanation:

Step1: Identify the dilution formula

$M_1V_1 = M_2V_2$

Step2: Identify the given values

$M_1=0.490\ M$, $V_1 = 600.0\ mL$, $V_2=900.0\ mL$

Step3: Solve for $M_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{0.490\ M\times600.0\ mL}{900.0\ mL}$
$M_2 = 0.327\ M$

Answer:

$0.327\ M$