Question

1. 78g pb(oh)₄10) 15.1g hno₃calculate the mass for the following-11) 2.25 moles c₄h₈12) 1.75 moles co₂s₃13) 3.0 moles nabr14) 4.3 moles pb(oh)₄15) .75 moles hno₃

Explanation:

For 11) 2.25 moles $\text{C}_4\text{H}_8$

Step1: Calculate molar mass

Molar mass of $\text{C}_4\text{H}_8$: $4\times12.01 + 8\times1.008 = 56.104\ \text{g/mol}$

Step2: Compute mass from moles

$\text{Mass} = \text{Moles} \times \text{Molar Mass} = 2.25 \times 56.104$

For 12) 1.75 moles $\text{Co}_2\text{S}_3$

Step1: Calculate molar mass

Molar mass of $\text{Co}_2\text{S}_3$: $2\times58.93 + 3\times32.07 = 214.03\ \text{g/mol}$

Step2: Compute mass from moles

$\text{Mass} = 1.75 \times 214.03$

For 13) 3.0 moles $\text{NaBr}$

Step1: Calculate molar mass

Molar mass of $\text{NaBr}$: $22.99 + 79.90 = 102.89\ \text{g/mol}$

Step2: Compute mass from moles

$\text{Mass} = 3.0 \times 102.89$

For 14) 4.3 moles $\text{Pb(OH)}_4$

Step1: Calculate molar mass

Molar mass of $\text{Pb(OH)}_4$: $207.2 + 4\times(16.00+1.008) = 275.232\ \text{g/mol}$

Step2: Compute mass from moles

$\text{Mass} = 4.3 \times 275.232$

For 15) 0.75 moles $\text{HNO}_3$

Step1: Calculate molar mass

Molar mass of $\text{HNO}_3$: $1.008 + 14.01 + 3\times16.00 = 63.018\ \text{g/mol}$

Step2: Compute mass from moles

$\text{Mass} = 0.75 \times 63.018$

Answer:

1. $126.234\ \text{g}$
2. $374.5525\ \text{g}$
3. $308.67\ \text{g}$
4. $1183.4976\ \text{g}$
5. $47.2635\ \text{g}$