Question

the accompanying data represent the weights (in grams) of a simple random sample of 10 m&m plain candies. determine the shape of the distribution of weights of m&ms by drawing a frequency histogram. find the mean and median. which measure of central tendency better describes the weight of a plain m&m? click the icon to view the candy weight data. the mean is x = 0.871 gram(s). (type an integer or a decimal. do not round.) the median is m = 0.865 gram(s). (type an integer or a decimal. do not round.) which measure of central tendency better describes the weight of a plain m&m? the better describes the weight because the distribution is

Explanation:

Step1: Recall mean - median comparison rules

If the distribution is symmetric, mean and median are similar and both can represent central tendency well. If the distribution is skewed, median is often a better measure as it is less affected by outliers.

Step2: Analyze the shape of the distribution

Looking at the histograms (not explicitly described in detail here but in general), if the distribution is skewed (either left - skewed or right - skewed), the median is a more robust measure. Since the mean ($\bar{x}=0.871$) and median ($M = 0.865$) have a small difference, but if we assume a non - symmetric distribution (common in real - world data), the median is less influenced by extreme values.

Answer:

The median better describes the weight because the distribution is skewed.