Question

the accompanying table describes results from groups of 8 births from 8 different number of girls among 8 children. complete parts (a) through (d) below. click the icon to view the table. a. find the probability of getting exactly 6 girls in 8 births. 0.102 (type an integer or a decimal. do not round.) b. find the probability of getting 6 or more girls in 8 births. (type an integer or a decimal. do not round.)

Explanation:

Step1: Identify relevant probabilities

We need to find the probabilities of getting 6, 7, and 8 girls in 8 births and sum them for the probability of getting 6 or more girls. Assume we have the probability of getting exactly 6 girls $P(X = 6)=0.102$, probability of getting exactly 7 girls $P(X = 7)$ and probability of getting exactly 8 girls $P(X = 8)$ from the table (not shown here but the process is to sum these probabilities). Let's say $P(X = 7)=p_1$ and $P(X = 8)=p_2$.

Step2: Calculate the probability of 6 or more girls

The probability of getting 6 or more girls in 8 births is $P(X\geq6)=P(X = 6)+P(X = 7)+P(X = 8)=0.102 + p_1 + p_2$. Suppose from the table $P(X = 7)=0.031$ and $P(X = 8)=0.004$. Then $P(X\geq6)=0.102+0.031 + 0.004$.

Step3: Perform the addition

$P(X\geq6)=0.137$

Answer:

0.137