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r added 7/10 of a cup of yellow raisins and 6 3/5 cups of black rai how…
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Question

r added 7/10 of a cup of yellow raisins and 6 3/5 cups of black rai how many cups of raisins did walter add in all? e your answer as a fraction or as a whole or mixed number. cups

Explanation:

Step1: Convert mixed number to improper fraction

The black raisins are \( 6\frac{3}{5} \) cups. To convert this mixed number to an improper fraction, we use the formula \( a\frac{b}{c}=\frac{a\times c + b}{c} \). So, \( 6\frac{3}{5}=\frac{6\times5 + 3}{5}=\frac{30 + 3}{5}=\frac{33}{5} \).

Step2: Find a common denominator for addition

The yellow raisins are \( \frac{7}{10} \) cups and the black raisins (now as an improper fraction) are \( \frac{33}{5} \) cups. The common denominator of 10 and 5 is 10. So we convert \( \frac{33}{5} \) to tenths: \( \frac{33}{5}=\frac{33\times2}{5\times2}=\frac{66}{10} \).

Step3: Add the two fractions

Now we add the amount of yellow raisins (\( \frac{7}{10} \)) and the converted amount of black raisins (\( \frac{66}{10} \)): \( \frac{7}{10}+\frac{66}{10}=\frac{7 + 66}{10}=\frac{73}{10} \).

Step4: Convert back to a mixed number (optional, but as per the problem's request for a mixed number or whole number)

\( \frac{73}{10}=7\frac{3}{10} \) (since \( 73\div10 = 7 \) with a remainder of 3).

Answer:

\( 7\frac{3}{10} \)