Question

1. al+cl2→alcl3

work:
answer:

1. n2+h2→nh3

work:
answer:

Explanation:

Step1: Balance the first equation

To balance $Al + Cl_2
ightarrow AlCl_3$, we need to make the number of atoms of each element equal on both sides. Chlorine has 2 atoms on the left - hand side and 3 on the right - hand side. The least common multiple of 2 and 3 is 6. So we put a 3 in front of $Cl_2$ and a 2 in front of $AlCl_3$. Then we need to put a 2 in front of $Al$. The balanced equation is $2Al + 3Cl_2=2AlCl_3$.

Step2: Balance the second equation

For $N_2 + H_2
ightarrow NH_3$, nitrogen has 2 atoms on the left - hand side and 1 on the right - hand side, and hydrogen has 2 atoms on the left - hand side and 3 on the right - hand side. We put a 1 in front of $N_2$, a 3 in front of $H_2$ and a 2 in front of $NH_3$. The balanced equation is $N_2+3H_2 = 2NH_3$.

Answer:

1. $2Al + 3Cl_2=2AlCl_3$
2. $N_2+3H_2 = 2NH_3$