Question

algebra i b-cr
the people who responded to a survey reported that they had either brown, green, blue, or hazel eyes. the results of the survey are shown in the table.
eye color | number of people
brown | 20
green | 6
blue | 17
hazel | 7
what is the probability that a person chosen at random from this group has brown or green eyes?
$\frac{3}{25}$
$\frac{7}{25}$
$\frac{13}{25}$
$\frac{17}{25}$

Explanation:

Step1: Calculate total survey respondents

$20 + 6 + 17 + 7 = 50$

Step2: Sum brown + green eye counts

$20 + 6 = 26$

Step3: Compute simplified probability

$\frac{26}{50} = \frac{13}{25}$

Answer:

$\frac{13}{25}$ (Option C)