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algebra 1 – first quarter classwork #3: lesson 1.4 – solving absolute v…

Question

algebra 1 – first quarter
classwork #3: lesson 1.4 – solving absolute value equations
name: adrianna george
period: 5th
score:
date: 9/3/25
direction: explore absolute value functions, recognize their v-shape, and identify the vertex.

part a: warm-up (dok 1 – recall)

  1. evaluate:

a. |-5| = ______
b. |7| = ______
c. |0| = ______

  1. in your own words, what does absolute value mean? ______

part b: finding the vertex (dok 2/3 – reasoning)

  1. find the vertex for each:

a. y = |x + 5| → vertex: ______
b. y = |x - 2| - 4 → vertex: ______
c. y = -|x - 1| + 3 → vertex: ______

  1. explain your reasoning for one of your answers: ______

part c: rigor question – analyze & compare (dok 3)

  1. compare the graphs of y = |x - 4| and y = -|x - 4|.

a. how are their vertices the same?
b. how are their shapes different?

part d: rigor question – real-world application (dok 4)

  1. a skateboard ramp has a v-shape modeled by the function y = |x| + 2.

a. what is the vertex?
b. what is the new equation if the ramp is shifted to the right by 3 units and up by 1 unit? what is the new vertex?

Explanation:

Response
Part A: Warm - Up
1. Evaluate
a. \(|-5|\)

Step1: Recall absolute value definition

The absolute value of a number \(a\) is \(|a|=

$$\begin{cases}a, & a\geq0\\-a, & a < 0\end{cases}$$

\). For \(- 5\), since \(-5<0\), \(|-5|=-(-5)\)

Step2: Calculate the result

\(-(-5) = 5\)

Step1: Recall absolute value definition

For \(7\), since \(7\geq0\), \(|7| = 7\)

Step1: Recall absolute value definition

For \(0\), \(|0|=0\) (by the definition of absolute value, the distance of \(0\) from \(0\) on the number line is \(0\))

Answer:

\(5\)

b. \(|7|\)