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analysis and conclusions 1. for each case in which you found a reaction…

Question

analysis and conclusions

  1. for each case in which you found a reaction occurred, write the correct formula for the substance formed. in those cases where no reaction occurred, mark nr (no reaction)
  2. for each formula write the correct chemical name for the compound formed. in those cases where no reaction occurred, mark nr (no reaction).

Explanation:

Step1: Recall solubility rules

Use solubility rules to determine if a reaction occurs and the product formed. For example, when a metal - ion reacts with an anion, if the resulting compound is insoluble, a reaction occurs.

Step2: Analyze each combination

For $Co(NO_3)_2$ and $K_3PO_4$

The reaction is $3Co(NO_3)_2 + 2K_3PO_4=Co_3(PO_4)_2\downarrow+6KNO_3$. The product is $Co_3(PO_4)_2$ (cobalt(II) phosphate).

For $Co(NO_3)_2$ and $KOH$

$Co(NO_3)_2 + 2KOH = Co(OH)_2\downarrow+2KNO_3$. The product is $Co(OH)_2$ (cobalt(II) hydroxide).

For $Co(NO_3)_2$ and $K_4Fe(CN)_6$

$3Co(NO_3)_2+2K_4Fe(CN)_6 = Co_3[Fe(CN)_6]_2\downarrow + 6KNO_3$. The product is $Co_3[Fe(CN)_6]_2$ (cobalt(II) hexacyanoferrate(II)).

For $Co(NO_3)_2$ and $K_2CO_3$

$Co(NO_3)_2+K_2CO_3 = CoCO_3\downarrow+2KNO_3$. The product is $CoCO_3$ (cobalt(II) carbonate).

For $Co(NO_3)_2$ and $KI$

$Co(NO_3)_2 + 2KI=CoI_2 + 2KNO_3$. Since $CoI_2$ is soluble, NR (no reaction).

For $Co(NO_3)_2$ and $K_2C_2O_4$

$Co(NO_3)_2+K_2C_2O_4 = CoC_2O_4\downarrow+2KNO_3$. The product is $CoC_2O_4$ (cobalt(II) oxalate).
Repeat this process for all the metal - ion and anion combinations.

Answer:

$K_3PO_4$$KOH$$K_4Fe(CN)_6$$K_2CO_3$$KI$$K_2C_2O_4$
$Pb(NO_3)_2$$Pb_3(PO_4)_2$$Pb(OH)_2$$Pb_2[Fe(CN)_6]$$PbCO_3$$PbI_2$$PbC_2O_4$
$CuSO_4$$Cu_3(PO_4)_2$$Cu(OH)_2$$Cu_2[Fe(CN)_6]$$CuCO_3$$CuI$ (with oxidation - reduction side - reaction possible, but mainly NR)$CuC_2O_4$
$Fe(NO_3)_3$$FePO_4$$Fe(OH)_3$$Fe_4[Fe(CN)_6]_3$$Fe_2(CO_3)_3$NR$Fe_2(C_2O_4)_3$
$Ni(NO_3)_2$$Ni_3(PO_4)_2$$Ni(OH)_2$$Ni_2[Fe(CN)_6]$$NiCO_3$NR$NiC_2O_4$
$Sr(NO_3)_2$$Sr_3(PO_4)_2$$Sr(OH)_2$ (soluble in large amounts of water, but may precipitate in concentrated solutions)$Sr_2[Fe(CN)_6]$$SrCO_3$NR$SrC_2O_4$
$AgNO_3$$Ag_3PO_4$$AgOH$ (which decomposes to $Ag_2O$)$Ag_4[Fe(CN)_6]$$Ag_2CO_3$$AgI$$Ag_2C_2O_4$
$K_3PO_4$$KOH$$K_4Fe(CN)_6$$K_2CO_3$$KI$$K_2C_2O_4$
$Pb(NO_3)_2$Lead(II) phosphateLead(II) hydroxideLead(II) hexacyanoferrate(II)Lead(II) carbonateLead(II) iodideLead(II) oxalate
$CuSO_4$Copper(II) phosphateCopper(II) hydroxideCopper(II) hexacyanoferrate(II)Copper(II) carbonateNRCopper(II) oxalate
$Fe(NO_3)_3$Iron(III) phosphateIron(III) hydroxideIron(III) hexacyanoferrate(II)Iron(III) carbonateNRIron(III) oxalate
$Ni(NO_3)_2$Nickel(II) phosphateNickel(II) hydroxideNickel(II) hexacyanoferrate(II)Nickel(II) carbonateNRNickel(II) oxalate
$Sr(NO_3)_2$Strontium phosphateStrontium hydroxideStrontium hexacyanoferrate(II)Strontium carbonateNRStrontium oxalate
$AgNO_3$Silver phosphateSilver oxide (from decomposition of $AgOH$)Silver hexacyanoferrate(II)Silver carbonateSilver iodideSilver oxalate