Question

assume that females have pulse rates that are normally distributed with a mean of μ = 72.0 beats per minute and a standard deviation of σ = 12.5 beats per minute. complete parts (a) through (c) below

a. if 1 adult female is randomly selected, find the probability that her pulse rate is less than 79 beats per minute.

the probability is
(round to four decimal places as needed.)

Explanation:

Step1: Calculate z - score

The formula for the z - score is $z=\frac{x-\mu}{\sigma}$, where $x = 79$, $\mu=72.0$, and $\sigma = 12.5$. So, $z=\frac{79 - 72.0}{12.5}=\frac{7}{12.5}=0.56$.

Step2: Find probability from z - table

We want to find $P(X\lt79)$, which is equivalent to $P(Z\lt0.56)$ when $X$ is normally distributed. Looking up the value of $P(Z\lt0.56)$ in the standard normal distribution table, we get $P(Z\lt0.56)=0.7123$.

Answer:

$0.7123$