assuming that \$\\sum_{i=0}^{n} a_i = 39\$ and \\(\\sum_{i=0}^{n} b_i…

$assuming that \$\\sum_{i=0}^{n} a_i = 39\$ and \\(\\sum_{i=0}^{n} b_i…$

assuming that \$\sum_{i=0}^{n} a_i = 39\$ and \$\sum_{i=0}^{n} b_i = 107\$, find the sum \$\sum_{i=0}^{n} (b_i - a_i)\$.

$\sum_{i=0}^{n} (b_i - a_i) = \sum_{i=0}^{n} b_i - \sum_{i=0}^{n} a_i$

$\sum_{i=0}^{n} (b_i - a_i) = 107 - 39$

$107 - 39 = 68$

68