Question

the atom and atomic theory test study guide

1. explain in detail the accomplishments of aristotle, the curies, bohr, chadwick, dalton,

democritus, pauli, planck, rutherford and thomson.

1. heed of my cats, \handsome jack,\ weighs a whopping 22.4 lbs. the vet tells me that

jack needs to come down to 15 lbs. calculate how many grams that jack needs to lose.

1. compare and contrast alpha, beta and gamma radiation.
2. draw a simple electromagnetic spectrum. draw arrows from increasing to decreasing energy,

frequency and wavelengths. what wavelengths have more than 1 type of wave? what are they?

1. explain the four forces of nature. list them from strongest to weakest.
2. what is max plancks formula? what does it help to explain?
3. compare and contrast quantum and classical state of an atom.
4. how many protons(p), neutrons(n), and electrons(e) in mg? (round the atomic masses to whole

numbers)

1. how many protons(p), neutrons(n), and electrons(e) in u? (round the atomic masses to whole

numbers)

1. how many protons(p), neutrons(n), and electrons(e) in bi? (round the atomic masses to whole

numbers)

1. how many protons(p), neutrons(n), and electrons(e) in au? (round the atomic masses to whole

numbers)

1. how many protons(p), neutrons(n), and electrons(e) in sr? (round the atomic masses to whole

numbers)

1. how many protons(p), neutrons(n), and electrons(e) in k? (round the atomic masses to whole

numbers)

1. use roygbiv to draw the visible spectrum and label which ends have higher/lower energy,

frequency and wavelengths.

1. compare and contrast the sizes of the atomic particles, electrons, neutrons and protons.

complete the following frequency problems. use the formula: 2.99792108m/s = c = l n.

1. a wave is 975nm; find its frequency.
2. a wave is 842000000hz; find its wavelength.
3. a wave is 500nm. whats its frequency?
4. a 4.29*1013hz wave. whats its wavelength?

draw bohr models (orbital box diagrams) for the following elemental atoms. 20) al, 21) n, 22)
ne, 23) li

Explanation:

Step1: Recall relevant physics formulas

The speed - of - light formula is $c = \lambda
u$, where $c = 2.99792\times10^{8}\text{m/s}$ is the speed of light, $\lambda$ is the wavelength, and $
u$ is the frequency.

Step2: Solve problem 16

First, convert the wavelength $\lambda = 975\text{nm}=975\times10^{- 9}\text{m}$ to SI units. Then, from $c=\lambda
u$, we can solve for $
u$: $
u=\frac{c}{\lambda}=\frac{2.99792\times10^{8}\text{m/s}}{975\times10^{-9}\text{m}}\approx3.075\times10^{14}\text{Hz}$.

Step3: Solve problem 17

Given $
u = 842000000\text{Hz}$, from $c = \lambda
u$, we can solve for $\lambda$: $\lambda=\frac{c}{
u}=\frac{2.99792\times10^{8}\text{m/s}}{842000000\text{Hz}}\approx0.356\text{m}$.

Step4: Solve problem 18

Given $\lambda = 500\text{nm}=500\times10^{-9}\text{m}$, from $c=\lambda
u$, we can solve for $
u$: $
u=\frac{c}{\lambda}=\frac{2.99792\times10^{8}\text{m/s}}{500\times10^{-9}\text{m}} = 5.99584\times10^{14}\text{Hz}$.

Step5: Solve problem 19

Given $
u = 4.29\times10^{13}\text{Hz}$, from $c=\lambda
u$, we can solve for $\lambda$: $\lambda=\frac{c}{
u}=\frac{2.99792\times10^{8}\text{m/s}}{4.29\times10^{13}\text{Hz}}\approx6.99\times10^{-6}\text{m}$.

Answer:

1. $\approx3.075\times10^{14}\text{Hz}$
2. $\approx0.356\text{m}$
3. $\approx5.99584\times10^{14}\text{Hz}$
4. $\approx6.99\times10^{-6}\text{m}$