Question

an atomic cation with a charge of +1 has the following electron configuration:
$\text{he} 2s^22p^6$
what is the chemical symbol for the ion?
how many electrons does the ion have?
how many $2p$ electrons are in the ion?

Explanation:

Step1: Calculate total electrons

Helium ([He]) has 2 electrons. Add electrons from $2s^2$ and $2p^6$: $2 + 2 + 6 = 10$

Step2: Find neutral atom electrons

Cation has +1 charge, so neutral atom has $10 + 1 = 11$ electrons (equal to protons, so atomic number 11 is Na). The ion is $\text{Na}^+$

Step3: Identify 2p electron count

From configuration $2p^6$, the number is 6.

Answer:

1. $\text{Na}^+$
2. 10
3. 6