Question

1. an automobile with an initial speed of 4.3 m/s accelerates uniformly at the rate of 3.0 m/s² for 5.0 s. find the:

a) final speed
b) displacement

Explanation:

Step1: Use velocity - time formula for final speed

$v = v_0+at$
where $v_0 = 4.3$ m/s, $a = 3.0$ m/s², $t = 5.0$ s.
$v=4.3 + 3.0\times5.0=4.3+15 = 19.3$ m/s

Step2: Use displacement - time formula

$x=v_0t+\frac{1}{2}at^{2}$
Substitute $v_0 = 4.3$ m/s, $a = 3.0$ m/s², $t = 5.0$ s.
$x=4.3\times5.0+\frac{1}{2}\times3.0\times5.0^{2}=21.5 + 37.5=59$ m

Answer:

a) 19.3 m/s
b) 59 m