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the average daily jail population in the united states is 706,242. if t…

Question

the average daily jail population in the united states is 706,242. if the distribution is normal and the standard deviation is 52,145. find the probability that on a randomly selected day, the jail population is greater than 750,000? in this problem, which of the following statements is correct? select the correct response: the area that is of no interest to the problem solver is less than 0.5. the lower bound is -9e99. my answer is not listed among the given choices. the upper bound is -9e99. the area of interest is greater than 0.5. the lower bound is -9e-99. the z score is negative. the mean of the distribution is centered at 706,242.

Explanation:

Step1: Identify given values

Mean $\mu = 706,242$, standard deviation $\sigma = 52,145$, target value $x = 750,000$

Step2: Calculate z-score

$z = \frac{x - \mu}{\sigma} = \frac{750000 - 706242}{52145} \approx 0.84$

Step3: Analyze each option

  1. Area of interest ($P(X>750000)$) corresponds to $z>0.84$, which is less than 0.5, so "The area of interest is greater than 0.5" is wrong.
  2. The uninteresting area is $1 - P(X>750000) > 0.5$, so "The area that is of no interest to the problem solver is less than 0.5" is wrong.
  3. The z-score is positive (~0.84), so "The z score is negative" is wrong.
  4. For upper tail probability ($X>750000$), lower bound is 750000, upper bound is $+\infty$ (not -9E99), so upper/lower bound options are wrong.
  5. The mean of the normal distribution is its center, so "The mean of the distribution is centered at 706,242" is correct.

Answer:

The mean of the distribution is centered at 706,242.