Question

bacl₂ + h₂so₄ → baso₄ + hcl
ba=
cl=
h=
s=
o=
ba=
cl=
h=
s=
o=

Explanation:

Step1: Balance barium (Ba)

On both sides, 1 Ba atom is sufficient, so coefficients for Ba - containing compounds remain 1 for now.

Step2: Balance chlorine (Cl)

There are 2 Cl atoms in $BaCl_2$. To balance Cl on the right - hand side, we put a coefficient of 2 in front of HCl.

Step3: Balance hydrogen (H)

There are 2 H atoms in $H_2SO_4$ and now 2 H atoms in 2HCl, so H is balanced.

Step4: Balance sulfur (S)

There is 1 S atom in $H_2SO_4$ and 1 S atom in $BaSO_4$, so S is balanced.

Step5: Balance oxygen (O)

There are 4 O atoms in $H_2SO_4$ and 4 O atoms in $BaSO_4$, so O is balanced.

Answer:

1 $BaCl_2$ + 1 $H_2SO_4$ $
ightarrow$ 1 $BaSO_4$ + 2 $HCl$