Question

a bag of m&ms has 6 red, 2 green, 5 blue, and 4 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places)
a) a yellow?
b) a blue or green?
c) an orange?

Explanation:

Step1: Calculate total number of M&M's

$6 + 2+5 + 4=17$

Step2: Calculate probability of picking a yellow

The number of yellow M&M's is 4. Probability formula is $P(A)=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P(\text{yellow})=\frac{4}{17}\approx 0.2353$

Step3: Calculate probability of picking a blue or green

The number of blue M&M's is 5 and green is 2. So number of favorable outcomes for blue or green is $5 + 2 = 7$. Then $P(\text{blue or green})=\frac{7}{17}\approx 0.4118$

Step4: Calculate probability of picking an orange

There are 0 orange M&M's. So $P(\text{orange})=\frac{0}{17}=0$

Answer:

a) $0.2353$
b) $0.4118$
c) $0$