Question

a bag of m&ms has 3 red, 6 green, 4 blue, and 5 yellow m&ms. what is the probability of randomly picking a. a yellow? leave answer as a reduced fraction. b. a blue or green? c. an orange?

Explanation:

Step1: Calculate total number of M&M's

$3 + 6+4 + 5=18$

Step2: Calculate probability of picking a yellow

Number of yellow M&M's is 5. Probability $P(\text{yellow})=\frac{\text{Number of yellow}}{\text{Total number}}=\frac{5}{18}$

Step3: Calculate probability of picking a blue or green

Number of blue is 4 and green is 6. So number of blue or green is $4 + 6=10$. Probability $P(\text{blue or green})=\frac{10}{18}=\frac{5}{9}$

Step4: Calculate probability of picking an orange

There are 0 orange M&M's. Probability $P(\text{orange})=\frac{0}{18}=0$

Answer:

a. $\frac{5}{18}$
b. $\frac{5}{9}$
c. $0$