Question

1. balance the following reactions: \\(\ce{albr_{3} + k_{2}so_{4} \

ightarrow kbr + al_{2}(so_{4})_{3}}\\)

Explanation:

Step1: Balance Al atoms

Add coefficient 2 to $\text{AlBr}_3$:
$2\text{AlBr}_3 + \text{K}_2\text{SO}_4
ightarrow \text{KBr} + \text{Al}_2(\text{SO}_4)_3$

Step2: Balance $\text{SO}_4^{2-}$ ions

Add coefficient 3 to $\text{K}_2\text{SO}_4$:
$2\text{AlBr}_3 + 3\text{K}_2\text{SO}_4
ightarrow \text{KBr} + \text{Al}_2(\text{SO}_4)_3$

Step3: Balance K and Br atoms

Add coefficient 6 to $\text{KBr}$:
$2\text{AlBr}_3 + 3\text{K}_2\text{SO}_4
ightarrow 6\text{KBr} + \text{Al}_2(\text{SO}_4)_3$

Step4: Verify atom counts

Check all atoms are equal on both sides:
Left: Al=2, Br=6, K=6, S=3, O=12
Right: K=6, Br=6, Al=2, S=3, O=12

Answer:

$2\text{AlBr}_3 + 3\text{K}_2\text{SO}_4
ightarrow 6\text{KBr} + \text{Al}_2(\text{SO}_4)_3$