balancing chemical equations
suggestions:
1. use a pencil, so that you can change coefficients if you make a mistake.
2. treat it like a puzzle, not a chore. it can be fun if you look at it as his is the best mr. glenister can give me. i laugh in the face of easy puzzles like this!\
3. write the number of atoms on each side of the equation. if a polyatomic appears on both sides of the equation, treat it as a single atom.
4. start with the most complicated compound, as putting a coefficient in front of it will change more atoms; then leave elements until the end, as you can put any coefficient in front of them.
5. you can only add coefficients in front of compounds, you cannot change the formula.
6. if you need to put a fractional coefficient on something in order to balance it, you can multiply everything by the denominator to clear the fraction.
example:
li + br₂ → libr (br is unbalanced)
1 li 1 li
2 br 1 br
li + br₂ → 2libr (to balance the br, but now li is unbalanced)
1 li 2 li
2 br 2 br
2li + br₂ → 2libr (to balance the li)
2 li 2 li
2 br 2 br
balanced!
ca(no₃)₂ + cu₂so₄ → caso₄ + cuno₃ (cu and no₃ are unbalanced)
1 ca 1 ca
2 no₃ 1 no₃
2 cu 1 cu
1 so₄ 1 so₄
ca(no₃)₂ + cu₂so₄ → caso₄ + 2cuno₃ (to balance cu, which also balanc
1 ca 1 ca
2 no₃ 2 no₃
2 cu 2 cu
1 so₄ 1 so₄
balanced!

Question

balancing chemical equations
suggestions:
1. use a pencil, so that you can change coefficients if you make a mistake.
2. treat it like a puzzle, not a chore. it can be fun if you look at it as 	his is the best mr. glenister can give me. i laugh in the face of easy puzzles like this!\
3. write the number of atoms on each side of the equation. if a polyatomic appears on both sides of the equation, treat it as a single atom.
4. start with the most complicated compound, as putting a coefficient in front of it will change more atoms; then leave elements until the end, as you can put any coefficient in front of them.
5. you can only add coefficients in front of compounds, you cannot change the formula.
6. if you need to put a fractional coefficient on something in order to balance it, you can multiply everything by the denominator to clear the fraction.
example:
li + br₂ → libr (br is unbalanced)
1 li 1 li
2 br 1 br
li + br₂ → 2libr (to balance the br, but now li is unbalanced)
1 li 2 li
2 br 2 br
2li + br₂ → 2libr (to balance the li)
2 li 2 li
2 br 2 br
balanced!
ca(no₃)₂ + cu₂so₄ → caso₄ + cuno₃ (cu and no₃ are unbalanced)
1 ca 1 ca
2 no₃ 1 no₃
2 cu 1 cu
1 so₄ 1 so₄
ca(no₃)₂ + cu₂so₄ → caso₄ + 2cuno₃ (to balance cu, which also balanc
1 ca 1 ca
2 no₃ 2 no₃
2 cu 2 cu
1 so₄ 1 so₄
balanced!

Accepted Answer

# Explanation:
## Step1: Analyze the unbalanced equation
We are given the un - balanced chemical equation $Ca(NO_3)_2+Cu_2SO_4
ightarrow CaSO_4 + CuNO_3$. We need to count the number of each type of atom on both sides. On the left - hand side: 1 Ca, 2 $NO_3$, 2 Cu, 1 $SO_4$. On the right - hand side: 1 Ca, 1 $NO_3$, 1 Cu, 1 $SO_4$. The Cu and $NO_3$ are unbalanced.
## Step2: Balance the Cu atoms
To balance the Cu atoms, we put a coefficient of 2 in front of $CuNO_3$ on the right - hand side. The equation becomes $Ca(NO_3)_2+Cu_2SO_4
ightarrow CaSO_4 + 2CuNO_3$.
## Step3: Check the balance of other atoms
After adding the coefficient 2 in front of $CuNO_3$, we check the number of other atoms. For Ca, we have 1 Ca on both sides. For $NO_3$, we have 2 $NO_3$ on the left - hand side and $2\times1 = 2$ $NO_3$ on the right - hand side. For Cu, we have 2 Cu on both sides. For $SO_4$, we have 1 $SO_4$ on both sides.
# Answer:
$Ca(NO_3)_2+Cu_2SO_4
ightarrow CaSO_4 + 2CuNO_3$

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QUESTION IMAGE

Question

Explanation:

Step1: Analyze the unbalanced equation

Step2: Balance the Cu atoms

Step3: Check the balance of other atoms

Answer: